msrance

03-13-2004, 03:21 AM

Hello Friends, I got this new idea when I was replying to a post in this very forum.Let me explain this to you.

When you wire the speakers in series, you connect the + terminal of one speaker to the - terminal of the next speaker. The elctricity flows through one speaker, and then on to the speaker.This increases the total resistance, reducing the total acoustical ouput. That is, because the electricity has to flow through each speaker one at a time, each speaker adds it's resistance to the whole. The formula is as follows:

Speaker 1 + Speaker 2 = Total Ohms Rating

8 Ohms + 8 Ohms = 16 Ohms

when you wire the speakers in parallel it reduces the total resistance increasing the total output. That is, because electricity flows through all of the speakers simultaneously, each speaker added reduces the resistance of the chain. If you visualize all of the negative electrons on one side trying to get to the other, they'll have an easier time because there are so many possible paths for them to go by.

Resistance = 1 / (1/speaker 1 + 1/speaker 2)

Resistance = 1 / (1 / 8 Ohms + 1 / 8 Ohms)

Resistance = 1 / (2/8)

Resistance = 1 / .25

Resistance = 4 Ohms

Now comes my querry :

1. The A and B speaker connections in an Amp are series or parallel conection?

2. What if I was to connect the 2 speakers in the A pair in series and the speakers in B pair also in series and put the two pairs in parallel?

3. You know some thing that brings the final value closer to 8 Ohms - compared to my present value of closer to 2.

Now let me tell you why this whole train of thought. I have a 100 W/C yamaha Amp @ 8 Ohms (capable of supposedly handling 4 and 2 ohms).

My A pair of speakers : I connect both pairs(L + R) of positive and negative terminals to the active subwoofer 100W @ 4ohm from where one connection goes to each of the pair (L + R) of 80 W @ 4 ohms speakers.

My B pair of speakers: each of the terminals goes to its respective 120 W @ 8 ohms speakers.

I believe at present this combines to give an impedence of 2.67 ohms approx. If I could rewire the whole bunch to get it as close to 8 ohms as possible. Thanks for the help in advance. I am also cross posting this in the DIY and tweaks section of the forum.

When you wire the speakers in series, you connect the + terminal of one speaker to the - terminal of the next speaker. The elctricity flows through one speaker, and then on to the speaker.This increases the total resistance, reducing the total acoustical ouput. That is, because the electricity has to flow through each speaker one at a time, each speaker adds it's resistance to the whole. The formula is as follows:

Speaker 1 + Speaker 2 = Total Ohms Rating

8 Ohms + 8 Ohms = 16 Ohms

when you wire the speakers in parallel it reduces the total resistance increasing the total output. That is, because electricity flows through all of the speakers simultaneously, each speaker added reduces the resistance of the chain. If you visualize all of the negative electrons on one side trying to get to the other, they'll have an easier time because there are so many possible paths for them to go by.

Resistance = 1 / (1/speaker 1 + 1/speaker 2)

Resistance = 1 / (1 / 8 Ohms + 1 / 8 Ohms)

Resistance = 1 / (2/8)

Resistance = 1 / .25

Resistance = 4 Ohms

Now comes my querry :

1. The A and B speaker connections in an Amp are series or parallel conection?

2. What if I was to connect the 2 speakers in the A pair in series and the speakers in B pair also in series and put the two pairs in parallel?

3. You know some thing that brings the final value closer to 8 Ohms - compared to my present value of closer to 2.

Now let me tell you why this whole train of thought. I have a 100 W/C yamaha Amp @ 8 Ohms (capable of supposedly handling 4 and 2 ohms).

My A pair of speakers : I connect both pairs(L + R) of positive and negative terminals to the active subwoofer 100W @ 4ohm from where one connection goes to each of the pair (L + R) of 80 W @ 4 ohms speakers.

My B pair of speakers: each of the terminals goes to its respective 120 W @ 8 ohms speakers.

I believe at present this combines to give an impedence of 2.67 ohms approx. If I could rewire the whole bunch to get it as close to 8 ohms as possible. Thanks for the help in advance. I am also cross posting this in the DIY and tweaks section of the forum.